Ajuggler throws a beanbag into the air with a speed of 1.0
how long does it take for the beanbag to reach its maximum height?
round the answer to two significant digits.
answer using a coordinate system where upward is positive.
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It takes for the beanbag 5/49 seconds to reach its maximum height

Explanation:

A juggler throws a beanbag into the air with a speed of 1.0

The initial speed is 1 m/s

The  beanbag will reach to its maximum height

At the maximum height the speed equal to zero

The final speed is zero

The acceleration of gravity = -9.8 m/s

We need to find how long it takes for the beanbag to reach its maximum

height

Lets use the rule: v = u + gt, where v is the final speed, u is the initial

velocity, t is the time and g is the acceleration of gravity

v= 0 , u = 1 , g = -9.8

0 = 1 - 9.8 t

Add two sides by 9.8 t

9.8 t = 1

Divide both sides by 9.8

t = 5/49 seconds

It takes for the beanbag 5/49 seconds to reach its maximum height

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.