Two particles with the same charges are held a fixed distance apart. the charges are equal in magnitude and they exert a force on each other. half of one of the charges is transferred to the other charge and the distance is unchanged. what happens to the force exerted by one charge on the other charge? the force is half as large the force is uncharged the force is twice as large the force is one fourth as large the force is three fourths as large

The force is three fourth as large of initial force

Explanation:

Let assume that that charge on each particle be q and the distance which is fixed between them be r.

Then By using Coulombs law the forcebetween them  is

When half of the charge is transferred from on to other particle then the charge on the particles are 0.5 q and 1.5 q

Let the force between them be

Then it can can be seen from taking taking ratio that

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

c) power lifting, will be your answer.

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