Suppose that on earth you can throw a ball vertically upward a distance of 1.20 m. given that the acceleration of gravity on the moon is 1.67 m/s2, how high could you throw a ball on the moon? (take the y-axis in the vertical direction, and assume that the location of your hand is at y = 0.)

7.04 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0

s = Displacement on Earth = 1.2 m

a = Acceleration due to gravity on Moon = 1.67 m/s²

a = Acceleration due to gravity Earth= 9.81 m/s²

Accelration going up is considered as negetive

Initial Velocity of the ball

Assuming that the ball is thrown with the same velocity on the Moon, displacement of the ball is

The displacement of the ball on the moon is 7.04 m

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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asthenosphere and convection