Calculate the heat, in kilocalories, that is absorbed if 183 g of ice at 0.0 ∘c is placed in an ice bag, melts, and warms to body temperature of 37.0 ∘c. the heat of fusion for water is 80. cal/g, or 334 j/g. the specific heat for water is 1.00 cal/g∘c, or 4.184 j/g∘c.

The total amount of heat needed will be .

Explanation:

We will divide the calculation in two: First, the heat needed to melt the ice, and then the heat needed to warm the resulting liquid from 0°C to 37°C.

i) The fusion heat will be:

ii) The heat needed to warm the water from to will be:

So, the total amount needed will be the sum of these two results:

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i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge