The length and width of a rectangular room are measured to be 3.92 ± 0.0035 m and 3.15 ± 0.0055 m. in this problem you can approximate the error on a product or quotient of quantities by the sum of the percent error on each quantity. a.) calculate the floor area of the room in square meters b.) calculate the uncertainty in this measurement in square meters.

A)

B)

Explanation:

Given:

Length of the room

Width of the room

A) Let A be the area of the room

B)We will calculate uncertainty in each dimension

%uncertainty in length

%uncertainty in width =

The uncertainty in area will be sum of uncertainty in length and width

%uncertainty in Area=  %uncertainty in length + %uncertainty in width

%uncertainty in Area

%uncertainty in Area=0.0106

Uncertainty in Area

There Area is

small = small current large mag large current

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day