Atrain moving with a velocity of 87.1 km/hour north, increases its speed with a uniform acceleration of 0.250 m/s2 north until it reaches a velocity of 160.0 km/hour north. what distance did the train travel while it was increasing its velocity, in units of meters?

2780 meters

Explanation:

First, convert km/hr to m/s.

87.1 km/hr × (1000 m / km) × (1 hr / 3600 s) = 24.2 m/s

160.0 km/hr × (1000 m / km) × (1 hr / 3600 s) = 44.4 m/s

Given:

v₀ = 24.2 m/s

v = 44.4 m/s

a = 0.250 m/s²

Find: x

v² = v₀² + 2a (x − x₀)

(44.4 m/s)² = (24.2 m/s)² + 2(0.250 m/s²) (x − 0 m)

x = 2780 m

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000

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