Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 c. the plates are 1.8 mm apart. what is the electric field (in n/c) at the center of the region between the plates? (enter the magnitude.)

E   = 5291.00 N/C

Explanation:

Expression for capacitance is

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

We know that capacitrnce and charge is related as

v = 9.523 V

Electric field is given as

   =

E   = 5291.00 V/m

E   = 5291.00 N/C

1 - wave length

2 - amplitude

3 - crest

4 - trough

explanation:

duh.

kepler used the data from tycho blahe (his mentor) to construct the laws of planetary motion.