The car traveling 56.0 km/h is 25.0 m towards a haystack when the driver brakes. the car hits the haystack 2.11 s later. how fast is the car traveling at impact? answer in m/s

36.13 m/s

Explanation:

initial speed, u = 56 km/h = 15.56 m/s

distance, s = 25 m

t = 2.11 s

Let the speed of the car at the impact is v and the acceleration is a.

Use second equation of motion

a = 9.75 m/s^2

Use first equation of motion

v = u + at

v = 15.56 + 9.75 x 2.11

v = 36.13 m/s

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.