The proton with initial v1 = 3.00 x 10^5 m/s enters a region 1.00 cm long where it is accelerated. its final velocity is v = 6.40 x 10^6 m/s . what was its constant acceleration. answer in 10^15 m/s^2

The constant acceleration,  

Solution:

As per the question:

length of the re region, l = 1 cm = 0.01 m

Now,

Using the third equation of motion:

answer: the rock sample is a sedimentary rock.

explanation:

it is given that:

mass of rock sample, m = 2.7 g

volume of rock sample,

so, density of rock sample will be

since, the density of rock sample is . hence, the rock sample is a sedimentary rock, whose densities varies between .

the area between the graph and the t axis