An electron enters a region of uniform electric field with an initial velocity of 50 km/s in the same direction as the electric field, which has magnitude e = 50 n/c, (a) what is the speed of the electron 1.5 ns after entering this region? (b) how far does the electron travel during the 1.5 ns interval?

(a). The speed of the electron is

(b). The distance traveled by the electron is

Explanation:

Given that,

Initial velocity = 50 km/s

Electric field  = 50 N/C

Time = 1.5 ns

(a). We need to calculate the speed of the electron 1.5 n s after entering this region

Using newton's second law

.....(I)

Using formula of electric force

.....(II)

from equation (I) and (II)

(a). We need to calculate the speed of the electron

Using equation of motion

Put the value of a in the equation of motion

(b). We need to calculate the distance traveled by the electron

Using formula of distance

Put the value in the equation

Hence, (a). The speed of the electron is

(b). The distance traveled by the electron is

for this one it would be d bump/forearm pass

no

sodium is solid at rt