Aproton, initially traveling in the +x-direction with a speed of 5.05×10^5 m/s , enters a uniform electric field directed vertically upward. after traveling in this field for 3.90×10^−7 s , the proton’s velocity is directed 45° above the +x-axis. what is the strength of the electric field?

The strength of the electric field is .

Explanation:

Given that,

Speed

Time

Angle = 45°

We need to calculate the acceleration

Using equation of motion

We need to calculate the strength of the electric field

Using relation of newton's second law and electric force

Put the value into the formula

Hence, The strength of the electric field is .

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000