Two particles, an electron and a proton, are initially at rest in a uniform electric field of magnitude 564 n/c. if the particles are free to move, what are their speeds (in m/s) after 49.6 ns?

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j

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d is correct as long as you put the state each one it eg. (aq)

mg(no3)2(aq) + zn(s) > zn(2+)(aq) + ) + mg(s)

hope it !