Aspring stretches 0.2 cm per newton of applied force. an object is suspended from the spring and a deflection of 3 cm is observed. if g = 9.81 m/s? , what is the mass of the object, in kg?

Explanation:

To solve this problem we use the Hooke's Law:

    (1)

F is the Force needed to expand or compress the spring by a distance Δx.

The spring stretches 0.2cm per Newton, in other words:

1N=k*0.2cm ⇒ k=1N/0.2cm=5N/cm  

The force applied is due to the weight

We replace in (1):

We solve the equation for m:

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.