The masses of the earth and moon are 5.98 x 1024 and 7.35 x 1022 kg, respectively. identical amounts of charge are placed on each body, such that the net force (gravitational plus electrical) on each is zero. what is the magnitude of the charge placed on each body?

The magnitude of charge on each is

Solution:

As per the question:

Mass of Earth,

Mass of Moon,

Now,

The gravitational force of attraction between the earth and the moon, if 'd' be the separation distance between them is:

       (1)

Now,

If an identical charge 'Q' be placed on each, then the Electro static repulsive force is given by:

          (2)

Now, when the net gravitational force is zero, the both the gravitational force and electro static force mut be equal:

Equating eqn (1) and (2):

Q =

true is the correct answer

hope i

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.