Three point charges are placed at the following locations: +4q at the origin, -2q at (x = -2, y = 0, z = 0) and -20 at (x = 2, y = 0 and z = 0). a. find the force on a fourth charge 5q placed at (x = 4, y = 6, z = 2) 6. find the force on a fourth charge 5q placed at (x, y, z) c. find locations where the force is solely in the (i) x direction, (ii) y direction, (iii) z direction d. is there any place where the force on the test charge is zero?

Ithink it’s cancer risk

+10 that is always the common denominator

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.