Arigid adiabatic container is divided into two parts containing n1 and n2 mole of ideal gases respectively, by a movable and thermally conducting wall. their pressure and volume are p1, v1 for part 1 and p2, v2 for part 2 respectively. find the final pressure p and temperature t after the two gas reaches equilibrium. assume the constant volume specific heats of the two gas are the same.

Explanation:

Given

Pressure, Temperature, Volume of gases is

Let P & T be the final Pressure and Temperature

as it is rigid adiabatic container  therefore Q=0 as heat loss by one gas is equal to heat gain by another gas

where Q=heat loss or gain (- heat loss,+heat gain)

W=work done by gas

change in internal Energy of gas

Thus from 1 & 2 we can say that

where

and

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )