Acentrifuge in a medical labarotary rotates at an
angularspeed of 3600 rev/min. when switch off, it rotates
through50.0 revolutions before coming to rest. find the
constantangular acceleration of the centrifuge.

angular acceleration = - 217.5 rad/s²

Explanation:

given data

angular speed = 3600 rev/min

rotate = 50 revolution

to find out

angular acceleration

solution

we know here no of rotation n =  3600 rev/min i.e 60 rev/s

so initial angular velocity will be  ω(i) = 2π× n

ω(i) = 2π× 60 = 376.9 rad/s

and

final angular velocity will be ω(f) = 0

so  

angular displacement will be  = 2π × 52 = 326.56 rad

and angular acceleration calculated as

angular acceleration =

put here value

angular acceleration =

angular acceleration = - 217.5 rad/s²

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