What uniform magnetic field, applied perpendicular to a beam
ofelectrons moving at 1.30 x 106 m/s, is required to
makethe elctrons travel in a ciruclar arc of radius 0.350 m?

The magnetic field is

Explanation:

Given that,

Speed

Radius = 0.350 m

We need to calculate the magnetic field

Using formula of magnetic field

Where, m = mass of electron

v = speed of electron

q = charge of electron

r = radius

Put the value into the formula

Hence, The magnetic field is

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s