Calculate the water pressure at the bottom of the marianas trench is approxi mately 1,100 kpa. with how much force would the water pressure at the bottom of the marianas trench push on a fish with a surface area of 0.50 m^2?

Force, F = 550000 N

Explanation:

Given that,

Pressure at the bottom of the Marianas Trench,

Surface area,

We need to find the force with which the water pressure at the bottom of the Marianas Trench push on a fish. Mathematically, the pressure is given by :

F = 550000 N

So, the force with which the water pressure at the bottom of the Marianas Trench push on a fish is 550000 N. Hence, this is the required solution.

it has to be b, about 97 percent.

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form