A1500kg space probe is moving at constant velocity of 4200m/sec. in a course change maneuver the rocket engines fire for 5 minutes increasing the probe's velocity to 5000m/sec. what is the probe's change in kinetic energy? a. 3.68x10^6 j. b. 5.52x10^9 j c. 1.1x10^10 j d. not enough info.

B)5.52x10^9 J

Explanation:

The equation for calculating kinetic energy is as follows

E=

so what we have to do is calculate the kinetic energy of the space probe in each state and calculate the difference

E=

E=

E=(1500)(5000^2-4200^2)/2

E=5.52x10^9 J

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be