What fraction of all the electrons in a 25 mg water
dropletmust be removed in order to obtain a net charge of 40
nc?

Explanation:

The water droplet is initially neutral, it will obtain a 40 nC of charge when a charge of  -40 nC is removed from the water droplet.

The charge on one electron,

Let the N number of electrons have charge -40 nC, such that,

Now, mass of one electron =

Therefore, mass of N electrons =

It is the mass of the of the water droplet that must be removed in order to obtain a charge of 40 nC.

Let it is m times the total mass of the droplet which is

Then,

It is the required fraction of mass of the droplet.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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as technology advances, new experiments often expose problems in accepted theories. c

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-lavira: )