An arrow, starting from rest, leaves the bow with a speed of25
m/s. if the average force exerted on the arrow by the bowwere
tripled, all else remaining the same, with what speed wouldthe
arrow leave the bow?

Explanation:

We can use the following kinematics equation

where is the final speed, its the initial speed, a is the acceleration, and d the distance.

The force will be tripled, the force is:

in 1D

Now, for the original problem, we have

For the second problem, we have

starting from the rest, we have the same initial velocity.

As the force is tripled, we have:

But the mass its the same,  so

So the acceleration its also tripled.

As the distance traveled by the arrow must also be the same, we have:

And this will be the speed from the arrow leaving the bow.

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.