Abullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of 5.80 ✕ 105 m/s2 for 9.60 ✕ 10−4 s. what is its muzzle velocity (in m/s) (that is, its final velocity)? (enter the magnitude.)

Final velocity will be 556.8 m/sec

Explanation:

We have given the average rate of change of velocity that is

Time

Initial velocity of bullet will be zero that is u=0

Now according to first law of motion

v=u+at, here v is final velocity, u is initial velocity and t is time

So

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer