Determine whether each of the following electron configurations is an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition metal. justify your choices.(a) 1s22s22p63s23p5(b) 1s22s22p63s23p63d74s2(c) 1s22s22p63s23p63d104s24p6(d) 1s22s22p63s23p64s1(e) 1s22s22p63s23p63d104s24p64d55s2(f) 1s22s22p63s2

The answer is below

Explanation:

(a) 1s22s22p63s23p5 it's a halogen, halogens are in group 7A in the periodic table, that means that that have 7 electrons in the outermost shell.

  outermost shell = 3   number of electrons = 2 + 5 = 7

(b) 1s22s22p63s23p63d74s2 it's an alkaline earth metal, these elements are in the 2A group and have 2 electrons in the outermost shell.

outermost shell 4 number of electrons = 2

(c) 1s22s22p63s23p63d104s24p6 This is an inert gas, these elements have 8 electrons in the outermost shell.

outermost shell 4 number of electrons = 2 + 6 = 8

(d) 1s22s22p63s23p64s1 This is a alkali metal, these elements have 1 electron in the outermost shell

outermost shell 4 number of electrons = 1

(e) 1s22s22p63s23p63d104s24p64d55s2  it's a transition metal. Besides this the outermost shell of this element is 5, shell 4 is incomplete, (4d5) letter d is for transition metal.

outermost shell 5, we consider 4  number of electrons (d) = 5

(f) 1s22s22p63s2  it's an alkaline earth metal, these elements are in the 2A group and have 2 electrons in the outermost shell.

outermost shell 3 number of electrons = 2

answer: i don't know the answer good luck

explanation:

v=ir = 3x15 =45 v