The steel ball a of diameter d = 25 mm slides freely on the horizontal rod of length l = 169 mm which leads to the pole face of the electromagnet. the force of attraction obeys an inverse-square law, and the resulting acceleration of the ball is a = k/(l - x)2, where k = 100 m3/s2 is a measure of the strength of the magnetic field. if the ball is released from rest at x = 0, determine the velocity v with which it strikes the pole face.

398 m/s

Explanation:

The acceleration is given by:

a = K/(L - x)^2

K = 100 m^3/s^2

L = 0.169 m

This acceleration will result in a force:

F = m * a

F = m * K/(L - x)^2

This force will perform a work:

W = F * L

The ball will advance only until x = L - D/2

This work will be converted to kinetic energy

W = Ek

Ek = 1/2 * m * v^2

First we solve thr integral:

We use the replacement

u = L - x

du = -dx

And the limits

When x = L - D/2, u = D2/2, and when x = 0, u = L

K / u evaluated between L and D/2

2*K / D - K / L

Then

1/2 * v^2 = 2*K / D - K / L

1/2 * v^2 = K * (2/D - 1/L)

v^2 = 2*K*(2/D - 1/L)

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!

c) power lifting, will be your answer.

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deku ❤