Wile e. coyote (carnivorous hungribilous) is chasing the roadrunner (speedibus cantcatchmi) yet again. while running down the road, they come to a deep gorge, 15 m straight across and 100 m deep. the roadrunner launches itself across the gorge at a launch angle of 15° above the horizontal, and lands with 1.5 m to spare.
(a) what was the roadrunner's launch speed? ignore air resistance.
(b) wiley coyote launches himself across the gorge with the same initial speed, but at a different launch angle. to his horror, he is short the other lip by 0.5 m. what was his launch angle? (assume that it was lower than 15°.)

What is the electric force acting between two charges of -0.0045 c and -0.0025 c that are 0.0060 m apart? use fe=kq1q2/r^2 and k = 9.00 x 10^9 n*m^2/c^2 a. 1.7 x 10^7 n b. -1.7 x 10^7 n c. -2.8 x 10^9 n d. 2.8 x 10^9 n

Arunner is jogging at a steady 3.6 km/hr. when the runner is 2.9 km from the finish line, a bird begins flying from the runner to the finish line at 14.4 km/hr (4 times as fast as the runner). when the bird reaches the finish line, it turns around and flies back to the runner. even though the bird is a dodo, we will assume that it occupies only one point in space, i.e., a zero-length bird. how far does the bird travel? (b) after this first encounter, the bird then turns around and flies from the runner back to the finish line, turns around again and flies back to the runner. the bird repeats the back and forth trips until the runner reaches the finish line. how far does the bird travel from the beginning? (i.e. include the distance traveled to the first encounter)

Aphoton is absorbed by an electron that is in the n = 3 state of a hydrogen atom, causing the hydrogen atom to become ionized. very far away from the nucleus, the released electron has a velocity of 750,000 m/s. what was the wavelength of the absorbed photon?