Atennis ball is dropped from 1.65 m above
the ground. it rebounds to a height of 0.99 m.
with what velocity does it leave the ground?
the acceleration of gravity is 9.8 m/s².
answer in units of m/s.

4.4 m/s

Explanation:

v² = v₀² + 2a(y − y₀)

(0 m/s)² = v₀² + 2(-9.8 m/s²)(0.99 m − 0 m)

v₀ = 4.4 m/s

Explanation:

As we know by the kinematics that final speed of the ball after it rebound will be zero as the ball will decelerate due to gravity.

here the displacement of the ball upwards is given as 0.99 m

so we will have

now we have

now by solving it we will have

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.

i will answer your question if you answer mine