Aphoton is emitted when a hydrogen atom undergoes a transition from the n = 8 state to the n = 4 state. calculate values for the following. (a) the wavelength nm (b) the frequency hz (c) the energy of the emitted photon ev

a) λ=2 μm

b)

c)E=0.61 eV

Explanation:

Given that

Hydrogen atom undergoes from n=8 to n= 4 state.

a)To find wavelength

We know that

Where

Now by putting the values

 λ=2 μm

b)For frequency

C= f x λ

c)To find energy

E= hf

E=0.61 eV

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.