Green light (λ = 518 nm) strikes a single slit at normal incidence. what width slit will produce a central maximum that is 3.00 cm wide on a screen 2.00 m from the slit? answer in μm .

6.9066 × 10⁻⁵ m

Explanation:

For constructive interference, the expression is:

Where, m = 1, 2, .....

d is the distance between the slits.

The formula can be written as:

....1

The location of the bright fringe is determined by :

Where, L is the distance between the slit and the screen.

For small angle ,

So,  

Formula becomes:

Using 1, we get:

Thus, the distance between the central maximum is 3.00 cm

First bright fringe , m = 1 occur at 3.00 / 2 = 1.50 cm

Since,

1 cm = 0.01 m

y = 0.0150 m

Given L = 2.00 m

λ = 518 nm

Since, 1 nm = 10⁻⁹ m

So,

λ = 518 × 10⁻⁹ m

Applying the formula as:

⇒ d, distance between the slits = 6.9066 × 10⁻⁵ m

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.