Compare a bound electron that executes harmonic oscillations at an angular frequency of w 1015 rad/s with a 0.5 kg mass oscillating at a frequency of w/2π 1.0 hz. (a) what are the ground state energies in each case? express your answers in ev (electron volts) (b) compute the amplitude of oscillation in classical mechanics that gives the ground state energy in quantum mechanics. carry out the computation for each case in turn. comment on the physical significance of the results, e. g., in what way do the numbers you obtain make (or not make) physical sense?

At maximum height, kinetic energy is converted in potential energy  formula: at max height, ke = ½ * 0.27kg * (16m/s) ² = 34.56 j  so the remaining pe = (41.70 – 34.56)= 7.14 j = 0.27 kg * 9.8m/s² * h  = (9.8/7.14 * 0.27)so max height h = 5.08 or 5 m 

330 wpu is be the right temperature

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.