Two charges are located in the x–y plane. if q1 = -2.90 nc and is located at x = 0.00 m, y = 0.840 m and the second charge has magnitude of q2 = 5.00 nc and is located at x = 1.00 m, y = 0.800 m, calculate the x and y components, ex and ey, of the electric field, , in component form at the origin, (0,0). the coulomb force constant is 1/(4π ε0) = 8.99 × 109 n·m2/c2.

Epx= - 21.4N/C

Epy= 19.84N/C

Explanation:

Electric field theory

The electric field at a point P due to a point charge is calculated as follows:

E= k*q/r²

E= Electric field in N/C

q = charge in Newtons (N)

k= electric constant in N*m²/C²

r= distance from load q to point P in meters (m)

Equivalences

1nC= 10⁻⁹C

known data

q₁=-2.9nC=-2.9 *10⁻⁹C

q₂=5nC=5  *10⁻⁹C

r₁=0.840m

Calculation of the electric field at point P due to q1

Ep₁x=0

Calculation of the electric field at point P due to q2

Calculation of the electric field at point P(0,0) due to q1 and q2

Epx= Ep₁x+ Ep₂x==0 - 21.4N/C =- 21.4N/C

Epy= Ep₁y+ Ep₂y=36.95 N/C-17.11N =19.84N/C

d eras and periods

mass and volume are the answers you are looking for