Light propagating in air strikes the surface of a lake. the reflected ray makes 62° angle with the normal. what angle does the refracted ray in the water makes with the normal. (hint: index of refraction for water 1.33) (a) 420 (b) 48° (c) 540 (d) 58° me= 9.11 × 10-31 kg 80-8.85 x 10-12 c/n. m2 h= 6.63 × 10-34 j-s m,-1.67 x 10-27 kg k-8.988 10 n -m/c e= 1.6× 10-19c o4t x 10-7 n/a pa 1.69 × 10-4 ω-m.

(a) 42°

Explanation:

According to the law of reflection:

Angle of incidence = Angle of reflection

So, angle of reflection = 62°

Angle of incidence = 62°

For refraction,

Using Snell's law as:

Where,  

 is the angle of incidence  ( 62.0° )

is the angle of refraction  ( ? )

is the refractive index of the refraction medium  (water, n=1.33)

is the refractive index of the incidence medium (air, n=1)

Hence,  

Angle of refraction = = 42°

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this is a good question! i'll do some research and come back when i have the answer!