Atall tube is evacuated and its stopcock is closed. the open end of the tube is immersed in a container of water (density 10^3 kg/m^3) that is open to the atmosphere (pressure 10^5 n/m^2). when the stopcock is opened, how far up the tube will the water rise?

10.19 m

Explanation:

Water will rise to equalize the pressure inside and outside the tube.

The equation of pressure is given by

Where,

p = Pressure of air = 10⁵ N/m²

ρ = Density of water = 10³ kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Height the water will rise

∴ The water will rise by 10.19 m.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

the duration of a photographic flash is related to an rc time constant, which is 0.100 μs for a certain camera.