According to the ideal gas law, a 1.074 mol sample of oxygen gas in a 1.746 l container at 267.6 k should exert a pressure of 13.51 atm. what is the percent difference between the pressure calculated using the van der waals' equation and the ideal pressure? for o2 gas, a = 1.360 l2atm/mol2 and b = 3.183×10-2 l/mol.

% differ  1.72%

Explanation:

given data:

P_ideal = 13.51 atm

n = 1.074 mol

V = 1.746 L

T = 267.6 K

According to ideal gas law we have

(P+0.514)(1.711) = 23.59

P_v = 13.276 atm

% differ

             = 1.72%

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