Aconcave mirror has a focal length of 30.0 cm. the distance between an object and its image is 45.0 cm. find the object and image dis- tances, assuming that (a) the object lies beyond the center of curvature and (b) the object lies between the focal point and the mirror.

object and image distances when object lies beyond center of curvature is 90 cm

object and image distances when object lies between focal point and mirror is 15 cm

Explanation:

given data

focal length f = 30.0 cm

distance between object and image = 45.0 cm

to find out

object and image distances

solution

we will apply here lens formula that is

(1/v) + (1/u) = (1/f)   1

and here v - u = 45

so v = 45 + u       2

so from equation 1

(1/(45+u)) + (1/u) = (1/30)

solve it we get u

u = 45 cm or -30 cm

so from equation 2

v = 45 + u

v = 45 + 45

v = 90 cm

object and image distances when object lies beyond center of curvature is 90 cm

and

v = 45 -30

v = 15 cm

object and image distances when object lies between focal point and mirror is 15 cm

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force