With the intensity at about half of maximum, how does the current change when you increase the frequency of the light?

Increase

Explanation:

Energy  of  given as follows

E = h f

Where f is the frequency of incident light

when high frequency light falls then it will increase the number of produce photon and that increase in number of photon will lead to increase in the number of electron.When number of electron will increase it mean that current will also increase.

So we can say that when frequency increase then current will increase.

i think the answer is a and b

i wish you luck

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m