Global positioning satellites (gps) can be used to determine positions w/great accuracy . the system works by determining the distance between the observer and each of several satellites orbiting earth . if one of the satellite is at a distance of 2 km from you . what percent accuracy in the distance is required if we desire a 2 meter uncertainty ? how many significant figures do we need to have in the distance ?

uncertainity = 0.0000001%

the no of significant figures need to have is eight

Explanation:

given data:

satellite distance from earth = 20000 k  = 20,000,000 m

we know that percntage of uncertainity of 2m can be calculated as

uncertainity = 0.0000001%

the range of satellite from your location from km to m is

(20,000,000m -2m) to (20,000,000m + 2m)  = 19999998 m  +20,000,002 m)

the no of significant figures need to have is eight

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.