Alaser beam is incident at an angle of 30.2â° to the vertical onto a solution of corn syrup in water. (a) if the beam is refracted to 18.50â° to the vertical, what is the index of refraction of the syrup solution? (b) suppose the light is red, with wavelength 632.8 nm in a vacuum. find its wavelength in the solution. nm (c) find its frequency in the solution. hz (d) find its speed in the solution. m/s

Explanation:

a ) Refractive index (μ ) = Sin i / Sin r

i is angle of incidence = 30.2 and r is angle of refraction = 18.5 degree

μ = Sin 30.2 / sin 18.5 = 0.5030 / .3173 = 1.585.

b ) Wave length  in a medium =  wavelength in air / refractive index

= 632.8 / 1.585 =  399.24 nm.

c ) frequency in solution = frequency in vacuum

=

= 47 x 10¹³ Hz

d ) Speed in the solution = Speed in vacuum / Refractive index

=

= 1.893 x 10⁸ ms⁻¹.