Aclosely wound circular coil has a radius of 6.00 cmand carries a current of 2.65 a. how many turns must it have if the magnetic field at its center is 6.31ã10^â4t?

Given:

radius of the coil, R = 6 cm = 0.06 m

current in the coil, I = 2.65 A

Magnetic field at the center, B =

Solution:

To find the number of turns, N, we use the given formula:

Therefore,

N = 22.74 = 23 turns (approx)

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