Two speakers are placed 4.5m apart, playing a coherent 660 hz tone. a listener is at a point 0.20 m from one speaker, on the line between the two speakers. the listener increases the frequency until the loudness they hear reaches a maximum. calculate the first frequency at which this occurs. take the speed of sound in air to be 344 ms-1.

The first frequency is 671 Hz.

Explanation:

Given that,

Frequency = 660 Hz

Distance from one speaker = 0.20 m

Distance between two speakers = 4.5 m

Speed of sound = 344 m/s

We need to calculate the path difference

Path difference = 4.3-0.20 =4.1 m

We need to calculate the frequency

Using formula of path difference

Here, n = 8

Because, the frequency is less then 660 Hz at n = 7.

Hence, The first frequency is 671Hz.

a high pressure system is a dense air mass that is usually cooler and drier than the surrounding air. a low pressure system is a less dense air mass that is usually wetter and warmer than the surrounding air.

in general, areas that experience high atmospheric pressure also experience fair weather. low pressure systems can cause the formation of clouds and storms. air usually flows from areas of high pressure to areas of low pressure..