Two metal spheres have a center to center separation of d=2m. sphere 1 has radius r1=.03m and charge q1=+1*x10^-8 c. sphere 2 has radius r2=2xr1 and charge q2=-3*x10^-8 c. assume the charge on each sphere is uniformly distributed. with v=0 at infinity, calculate the potential on the surfaces of sphere 1 and sphere 2.

V₁ =2865 V

V₂ = -4455 V.

Explanation:

Given:

Charge on sphere 1 = q₁ = 1 × 10⁻⁸ C

Charge on the sphere 2 = q₂ = -3 ×10⁻⁸ C

Radius of sphere 1 = R₁ = 0.03 m

Radius of sphere 2 = R₂ = 2 R₁ =0.06 m

Distance between the two spheres = d = 2 m

Potential on the sphere 1 = V₁ = where k is the Coulomb's constant.

⇒ V₁ = = 2865 V

Similarly, Potential on V₂ = = -4455 V.