At what rate must the potential difference between the plates of a parallel-plate capacitor with a 2.0 μf capacitance be changed to produce a displacement current of 1.4 a?

7 x 10^5 V/s

Explanation:

capacitance, C = 2 micro farad = 2 x 10^-6 F

displacement current, id = 1.4 A

Let dV/dt be the rate of change of potential difference between the plates of the capacitor.

The relation between the displacement current and the rate of change of potential difference is given by

dV/dt = 7 x 10^5 V/s

Thus, the rate of change of potential difference between the plates is given by 7 x 10^5 V/s.

found in the nucleus

has mass of one amu

v 154.9= 0.9 length length s little over 154.9cm