Initially, 1.00 mol of an ideal monatomic gas has 75.0 j of thermal energy. part a if this energy is increased by 22.0 j , what is the change in entropy?

Δ S = 2.51 × 10²³ J/K

Explanation:

change of entropy formula

N = 6.02 × 10²³ atoms

Initial thermal energy = Eₙ = 75 J

Final thermal energy,

Eₓ = 75 J  + 22 J

Eₓ = 97 J

Δ S = 2.51 × 10²³ J/K

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your answer is c! hope this : )