On a ride called the detonator at worlds of fun in kansas city, passengers accelerate straight downward from rest to 45 mi/h in 2.2 seconds. what is the average acceleration of the passengers on this ride?

Explanation:

It is given that,

Initial velocity of passengers, u =0

Final velocity of passengers, v = 45 mi/h = 20.11 m/s

Time taken, t = 2.2 s

We need to find the acceleration of the passengers on this ride. It can be calculated using the formula of acceleration as :

So, the acceleration of the passengers on this ride is . Hence, this is the required solution.

a=d/t

a="triangle"v/t

explanation:

a = acceleration

answer(20) psi;