Train a is moving 40m/s east. train b is moving 30m/s east. train a is gaining on train b and engineer a would like to avoid a collision with train b, if possible. assume the front of train a is 110m from the rear of train b, when engineer a reacts to the imminent collision. after reacting, engineer a applies train a’s brakes and decelerates at 0.5m/s2.

Shy diving is the only sport which doesnot require a high level of physical fitness

The big glowy thing is called the sun it is a star in our galaxy and is over 1 million degrees

It is the areas with lines. this may sound a little confusing, but i hope it !

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.