Consider a double-slit with a distance between the slits of 0.04 mm and slit width of 0.01 mm. suppose the screen is a distance of 1 m from the double-slit and light with a wavelength of 600 nm is illuminating the slits. what is the distance δxa between the places where the intensity is zero due to the single slit effect? give answer in mm to two significant figures. what is the distance δxd in mm between the places where the intensity is zero due to the double slit effect?

The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

Explanation:

Given that,

Distance between the slits = 0.04 mm

Width = 0.01 mm

Distance between the slits and screen = 1 m

Wavelength = 600 nm

We need to calculate the distance between the places where the intensity is zero due to the double slit effect

For constructive fringe

First minima from center

Second minima from center

The distance between the places where the intensity is zero due to the double slit effect

Put the value into the formula

Hence, The distance between the places where the intensity is zero due to the double slit effect is 15 mm.

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get