Amagnetic field has a magnitude of 0.078 t and is uniform over a circular surface whose radius is 0.10 m. the field is oriented at an angle of ø= 25° with respect to the normal to the surface. what is the magnetic flux through the surface?

Magnetic flux,

Explanation:

It is given that,

Magnitude of the magnetic field, B = 0.078 T

Radius of circular loop, r = 0.1 m

The field is oriented at an angle of θ = 25° with respect to the normal to the surface. The magnetic flux through the surface is given by :

or

So, the magnitude of magnetic flux through the surface is . Hence, this is the required solution.

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