Acircular cross section, d = 25 mm, experiences a torque load, t = 25 n·m, and a shear force, v = 85 kn. calculate the largest shear stress within the cross section. b. 239 mpa a. 231 mpa c. 8.15 mpa d. 95.6 mpa

largest shear stress = 239 N/mm²

Explanation:

Given data

cross section d = 25 mm

torque load T = 25 N·m

shear force V = 85 kN

to find out

largest shear stress

solution

we know that maximum shear stress due to load = 16T / πd³

maximum shear stress = 16 ( 25) / π(25)³

maximum shear stress = 8.148 N/mm²    ........................1

maximum shear stress due to force = 14/3 × avg shear stress

maximum shear stress due to force = 14 × 85 ×  / (3 ×π/4×25²)

maximum shear stress due to force = 230.88 N/mm²    ..................2

so

largest shear stress add equation 1 and 2

largest shear stress = 8.148 + 230.88

largest shear stress = 239 N/mm²

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

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