Acharged particle is moving through a constant magnetic field. does the magnetic field do work on the charged particle? a. yes, because the force is acting as the particle is moving through some distanceb. no, because the magnetic force is always perpendicular to the velocity of the particlec. no, because the magnetic field is a vector and work is a scalar quantityd.

Option B

Explanation:

When a charged particle moves in a constant magnetic field it experiences a force in a direction perpendicular to its motion, therefore changing the direction of motion of particle where the speed of the particle remains same.

Since the force is in perpendicular direction to the direction of motion of the particle, there is no work done by the magnetic field on the charged particle.

Therefore, when a charge particle moves through a constant magnetic field, no work is done by the magnetic field on the charge particle.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂