Acircular swimming pool has a diameter of 24 ft, the sides are 5 ft high, and the depth of the water is 4 ft. how much work is required to pump all of the water out over the side. density of water= 62.5 lb/a circular swimming pool has a diameter of 24 ft,. show all steps. the answer is [w= 108,000a circular swimming pool has a diameter of 24 ft, ft-lb]

W = 108000 π

Explanation:

Given data

diameter = 24 ft = so r = 24/2 = 12 ft

high = 5 ft

depth = 4 ft

Density of water= 62.5 lb

to find out

How much work is required

solution

we will apply here weight equation that i s

dW = density × area

artea = πr²

so that Work done wil be F  ×  d

we know w  = 62.5  

so

W = 62.5 πr²   (x+1) dx

W = 62.5 π(12)²  

W = 62.5 π(144)  (12)

W = 108000 π

hence W = 108000 π

this could be newton#'s law of cooling. the cooling curve is exponential